$(".btn-logo-img").click(function(){
var subir_btn = document.getElementById("logo");
subir_btn.click();
});
.logo is an input of type file, as it looks very ugly I created the .btn-logo-img of type button, when pressing this I intend to activate the other.
What I pretend is that .logo is always hidden, and that .btn-logo-img does the hidden function is to say that open the popup to upload file.
Note: The logo can NEVER be displayed