I have this script currently showing me the repeated numbers between 2 arrays but I can not do it to show me the repeated numbers and if their position matches
var number_load = [2,3,4,1]
var number_input = [9,5,3,1]
for(var numbers in number_load){
if(number_input.indexOf(number_load[numbers])>-1){
console.log('Se repite el numero : ' + number_load[numbers])
}
}If you are not planning to do this procedure in gigantic arrangements and if the two arrangements will always be the same size, I think you can go through the arrangements manually.
var number_load = [2,3,4,1];
var number_input = [9,5,3,1];
for(var i = 0; i < number_load.length; i++){
for(var j = 0; j < number_input.length; j++){
if(number_load[i] == number_input[j])
if(i == j)
console.log('Se repite el numero : ' + number_load[i] + ' en la posición '+ (i + 1))
else
console.log('Se repite el numero : ' + number_load[i] + ' pero su posicion no coincide ')
}
}Note that we are comparing the first array against the second and that the position shown in the message is for end users (the true position plus one).
Here you have the solution you should compare the position of the element in the two vectors with indexOf and see if they match.
var number_load = [2,3,4,1]
var number_input = [9,5,3,1]
for(var numbers in number_load){
if(number_input.indexOf(number_load[numbers])>-1){
console.log('Se repite el numero : ' + number_load[numbers])
if(number_input.indexOf(number_load[numbers]) ==
number_load.indexOf(number_load[numbers])){
console.log("coincide lugar del numero " + number_load[numbers]);
}
}
}