We want to make a program that receives a sequence of integers, the first of which will indicate the number of numbers to be read, and order the sequences.

When we find a sequence we will order, from least to greatest, all the elements belonging to that sequence. Once all the sequences are ordered, all the numbers ordered in their sequences will be shown on the screen.

```
Entradas
9 5 4 3 6 3 7 1 7 5
Salidas
3 4 5 6 1 3 7 5 7
```

This is what I take to the moment but what I try to do does not work

```
let cad = [];//SECUENCIAS
let numero = Number(prompt("Numero"));
let cad1 = new Array(numero);
for (let i=0;i<numero;i++){
cad[i] = Number(prompt('Numero ${i+1}'));}
for (let i=0;i<numero;i++) {
for (let j=0;j<numero;j++){
while (cad1[i].indexOf(cad[j])<1){
cad1.push(cad[j]);}
}}
```

I want that at the moment of finding a repeated cut there, I ordered it and continued with the same cycle where I stayed and store the sequences together to print them.

¡EDIT !!: I need that if it is already 5,4,3,6 (the following is a 3, so it is not added because it is repeated) then I order and it remains 3,4,5,6 and start again from 3 and it is 3,7,1 (because it follows 7 and does not enter because it is repeated) and now I order 1,3,7 and to finish I order the 5.7-- The "9" only represents how many numbers are going to enter. Thank you very much