How to travel AJAX MVC?

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How to travel AJAX MVC?

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#1 by (0 votes)

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I have problems when showing the message of the controller does not enter the function does not print the alert

HTML

<button type="submit" name="pdp_grafico" onclick="pdp_grafico();">PDP</button>

JS

<script src="js/jquery.min.js"></script>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

<script src="js/highstock.js"></script>
<script src="js/exporting.js"></script>
<script src="js/bootstrap.min.js"></script>
<script src="js/jquery.dataTables.min.js"></script>
<script>

    $(document).ready( function () 
    {
        $('#tabla').DataTable();
    });

    function pdp_grafico()
    {
        $.ajax({
            method:'GET',
            url:'controllers/HomeController.php/Prueba'
        }).done(function(data) 
        {
            alert(data);
        });
    }

</script>

CONTROLLER

<?php

require_once($_SERVER['DOCUMENT_ROOT']."/_class/DBConneccion.class.php");
require_once $_SERVER['DOCUMENT_ROOT'].'/_class/DB.php';

class HomeController extends DBConneccion 
{
    public function  __construct()
    {
        parent::__construct("chonchon");
    }

    function Prueba()
    {
        header('Content-type: application/json');  

        echo json_encode("Mensaje desde el controller"); 
    }
}

jquery html php ajax

asked by Juan Perez 19.10.2018 в 14:01

source

1 answer

Select specific cells from a csv file Car rental, python have more than one car available

score 0 · Answer 1

Try removing the onclick function, give the button an ID and try this:

<button type="submit" id="boton" name="pdp_grafico">PDP</button>

and the method would leave it like this:

   $("#boton").on('click',function(){

      $.ajax({

        url:"controllers/HomeController.php/Prueba",
        method:"GET",
        dataType:"Json",
        success:function(data){

        },
        error:function(data){
        alert("no se ha podido hacer");
        }   
     });
  });
})