Let's see if someone can help me because I'm stuck at this point. What I'm doing is a test with firebase and its database (Cloud Firestore) + angularjs. This is the following code:
// Initialize Firebase
var config = {
apiKey: "xxxxx",
authDomain: "xxxxx.firebaseapp.com",
databaseURL: "https://xxxxx.firebaseio.com",
projectId: "xxxxx",
storageBucket: "xxxxx",
messagingSenderId: "xxxxx"
};
firebase.initializeApp(config);
// Initialize Cloud Firestore through Firebase
var db = firebase.firestore();
// Add a new document in collection "cities"
var docRef = db.collection("test").doc("prueba1");
var app = angular.module('myApp', []);
app.controller('myCtrl', function($scope, $http) {
$scope.firstName = "John";
//console.log('aaa',docRef.get());
docRef.get().then(function(doc) {
if (doc.exists) {
var docdata = doc.data();
//console.log(doc.data());
//console.log("$scope", doc.data().Entrenador);
//console.log("$scope doc", doc.data());
$scope.characters = doc.data();
console.log("$scope chars", $scope.characters );
} else {
// doc.data() will be undefined in this case
console.log("Datos no encontrados!");
}
}).catch(function(error) {
console.log("Error al obtener los datos:", error);
});
console.log('Scope!!', $scope);
});
<div ng-controller="myCtrl">
Name: <input type="text" ng-model="firstName"><br>
<b>Name</b>: {{ firstName }}<hr>
<div ng-repeat="character in characters">
{{ character.name}}
</div>
{{characters.length}}
</div>
<script src="https://code.jquery.com/jquery-3.3.1.min.js" integrity="sha256-FgpCb/KJQlLNfOu91ta32o/NMZxltwRo8QtmkMRdAu8="crossorigin="anonymous"></script>
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.6.9/angular.min.js"></script>
<script src="https://www.gstatic.com/firebasejs/4.12.1/firebase.js"></script>
<script src="https://www.gstatic.com/firebasejs/4.12.1/firebase-firestore.js"></script>
When I try to show the data that is in "characters" it does not return anything (it does not give an error either). But the console.log of
console.log ("$ scope chars", $ scope.characters);
if it returns information. On the other hand if he returns me correctly John.
Thank you very much for everything:)