I need help with the submission of a form and at the same time I generate the report of the data sent by it, that is to say that by pressing the save button the data is inserted (part that I already have made) but that also direct me to the generated report, my code is as follows:
Here I start sending the form
$(document).on('click', '.btn-submit', function(ev){
ev.preventDefault();
var btn_button = $(this);
if($("#formcita").valid() == true){
var data = $("#formcita").serialize();
btn_button.html(' <i class="fa fa fa-spinner fa-spin"></i> Procesando...');
btn_button.attr("disabled",true);
$.post('save_cita.php', data, function(data,status){
console.log("Data: " + data + "\nStatus: " + status);
if( data == "1"){
//alert("Data: " + data + "\nStatus: " + status);
$(".alert-danger").hide();
$(".alert-success").fadeIn(800);
btn_button.html('<i class="fa fa fa-check-circle"></i> Hecho');
setTimeout(function(){ location.reload(); }, 2000);
}
else{
//alert("Data: " + data + "\nStatus: " + status);
$(".alert-success").hide();
$(".alert-danger").fadeIn(800);
btn_button.html('Guardar').attr("disabled",false);
}
});
}
});
});
** then I receive it in this file for the insertion process **
if($form_name == 'add_cita'){
$fcita = mysqli_real_escape_string($mysqli, $_POST['fcita']);
$hcita = mysqli_real_escape_string($mysqli, $_POST['hcita']);
$coment = mysqli_real_escape_string($mysqli, $_POST['coment']);
$numdon = mysqli_real_escape_string($mysqli, $_POST['numdon']);
$numafi = mysqli_real_escape_string($mysqli, $_POST['numafi']);
$query = "INSERT INTO citas (fechaCita,horaCita,comentario,dui_donantes,afi_pacientes)
values('$fcita','$hcita','$coment','$numdon','$numafi')";
$result = $mysqli->query($query) or die($mysqli-> connect_error);
if($result)
echo "1";
else
echo "0";
}
If someone has any suggestion or idea that I could add to my code to do the above, in advance thank you very much.