Send checkbox data when clicking on the input

I update the question:

I'm trying to find a way to create a functional I like button. For this I have thought about creating a small <form> in which there is an input type checkbox and a label, which is an icon. Visually only the label is seen since the checkbox is hidden.

I can not get the data sent to PHP or javascript when I click on the label, I would prefer javascript and then pass it to PHP.

HTML Code:

<form  name='like' id='heart' title='Me gusta el post' action='foro.php?foro=Xbox%20One&subforo=General&hilo=Vamos%dale&ID=1' method='post'>
 <input type='checkbox' id='corazon' name='corazon'>
 <label class='fa fa-heart' onclick='myFunction($respuesta_id)' for='corazon'></label>";
</form>

PHP:

echo $like = isset($_POST['corazon'])? $_POST['corazon'] : 0;

The value of $like is always 0.

JS:

<script>
    function myFunction(respuesta_id) {
      let heart;
      var id_respuesta = respuesta_id;

      if( $('#corazon').prop('checked') ) {
        console.log('Seleccionado');
        heart = 1;
      } else {
        console.log('No seleccionado');
        heart = 0;
      }
      console.log(id_respuesta);
      console.log(heart);

      $.ajax ({
        type: 'POST',
        url: 'proces_like.php',
        data: { "corazon": heart, "id_respuesta":id_respuesta },
        success:function(datos){
          $("#resultado").html(datos);
        }
      });
    };
</script>

I have to pass two parameters to PHP, on the one hand the value of heart and on the other the ID , which is nothing more than to identify the comment referred to by that "I like".

In PHP I can show the value of heart but not the ID , because it is not a value that can be obtained in the same way with the POST method, since it is not an input.