function c(n) {
var v;
if (n % 1 !== 0) v = parseFloat(n); // Verifico si el numero es decimal y uso parseFloat
else v = parseInt(n); // Verifico si el numero es entero y uso parseInt
return v; // Retorno el numero
}
console.log(c("45.2")); // Llamo a la función Assuming that JavaScript did not transform the string into numbers, how could you verify that n%1 , if it were first would be a string ?
So you can validate if it's a string
function esString(myVar){
return (typeof myVar == 'string' || myVar instanceof String);
}
console.log(esString(1));
console.log(esString("1"));
console.log(esString(new String(1)));And it is always advisable to parse string to numbers
function esString(myVar){
return (typeof myVar == 'string' || myVar instanceof String);
}
function suma(var1, var2){
var numVar1 = var1;
var numVar2 = var2;
if(esString(var1)){
if(var1.indexOf(".")>=0)
numVar1 = parseFloat(var1);
else
numVar1 = pareseInt(var1, 10);
}
if(esString(var2)){
if(var2.indexOf(".")>=0)
numVar2 = parseFloat(var2);
else
numVar2 = pareseInt(var2, 10);
}
console.log( numVar1 + numVar2 );
}
suma("5.2", 12); What I can understand about your question is that javascript does the conversion on its own and you want to know how it would be verified if a string is decimal if javascript did not do the conversion automatically. Well in this case just looking if you have a point with indexOf() , since decimals will always be accompanied by a period:
function c(n) {
var v;
if (n.indexOf(".") > -1){
console.log("decimal")
v = parseFloat(n);
}else {
console.log("int")
v = parseInt(n);
}
return v; // Retorno el numero
}
console.log(c("454.42"));
console.log(c("42")); Or with regular expressions looking for a point in the middle of numbers:
function c(n) {
var v;
if (/\d+\.\d+/g.test(n)){
console.log("decimal")
v = parseFloat(n);
}else {
console.log("int")
v = parseInt(n);
}
return v; // Retorno el numero
}
console.log(c("454.42"));
console.log(c("42"));