var a = {
edades = [12,15,16,2,12,45,60,15]
};
for(var i=0;i<a;i++) {
console.log("Soy:" +i);
}
As a story if there are repeated numbers in array ages, and if they repeat only execute the instructions once (but only for that element) ?
In other words, if there were:
var b = [1,2,3,4,5,6,7,1];
The one that is repeated is 1, then it would show:
,2,3,4,5,6,7,1 and the first 1 not since it is repeated
The simplest way is to convert the Array into a data type "Set". A set (Set) does not contain repeated elements.
An example:
var a = [1, 1, 2, 3]
var b = new Set(a)
b.forEach(x => console.log(x))
Exit:
1
2
3
Update
In that case, you can do it like this:
> var a = [1,2,3,4,5,6,7,1,1]
> var b = new Set()
> a.reverse().forEach(x => b.add(x))
> c = Array.from(b).reverse()
Value of c :
Array [ 2, 3, 4, 5, 6, 7, 1 ]
In this code I use an associative array, whose key of the elements is the number of the array ages.
In the first pass of the array ages I create the associative array to control that in the second pass we only take out each element once.
var a = {
edades : [1,2,3,4,5,6,7,1,1]
};
// Array para controlar si hemos sacado ya o no un elemento
var aListar = {};
// Array asociativo en el que me guardo si tengo que sacar el elemento en el listado (true) o si ya lo he sacado antes (false). La clave del array es el elemento origen
for (var i = 0; i < a.edades.length; i++) {
aListar[a.edades[i]] = true;
}
var cad = ''; // Cadena para sacar los elementos finales en el mismo orden
// Empiezo a leer el array origen por detrás
for (var i = a.edades.length; i>0; i--) {
if ( aListar[a.edades[i]] ) {
// Su elemento del array asociativo está a true, por lo que no he listado este elemento aún
aListar[a.edades[i]] = false; // Marco para no sacarlo más veces
cad = ',' + a.edades[i] + cad;
}
}
document.write( cad );