How can I remove a field from a multidimensional array?

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How can I remove a field from a multidimensional array?

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#1 by (2 votes)

2

You see I have a multidimensional array and I need to remove a field from that array but I can not get it.

I must clarify that I am using firestore firestore.

That's my code:

db.collection("database").doc("users").get().then(data => {
    var arrs = data.users;
    var remove = [{ name: "Juan" }, { name: "Alex" }]; // Este valor lo obtengo dependiendo de los checkbox's seleccionados
    var newArr = [];
    for (var i = 0; i < arrs.length; i++) {
        var index = arrs[i].indexOf(remove);
        if (index !== -1) {
            newArr.push(data.users.splice(i, 0));
        }
    }
    db.doc("database/users").update({
        users: newArr
    });
});

This is the JSON that returns to me when I make the list of users:

{
    "users": [{
        "name": "Juan"
        "ave": 23
    }, {
        "name": "Alex",
        "age": 17
    }, {
        "name": "Josefina",
        "age": 18
    }, {
        "name": "Carla",
        "age": 25
    }]
}

What I was supposed to return to me when I removed the indicated fields would be this:

{
    "users": [{
        "name": "Josefina",
        "age": 18
    }, {
        "name": "Carla",
        "age": 25
    }]
}

I need help, it took more than 2hrs trying to find a solution. Thank you very much

javascript firebase

asked by Eddy Otsutsuki 01.11.2018 в 08:39

source

1 answer

How to play an mp3 every x minutes when entering a page SQL query Advanced filter with Postgres

score 2 · Accepted Answer

You can use filter to eliminate those indicated elements.

let usersObj = JSON.parse('{
    "users": [{
        "name": "Juan",
        "ave": 23
    }, {
        "name": "Alex",
        "age": 17
    }, {
        "name": "Josefina",
        "age": 18
    }, {
        "name": "Carla",
        "age": 25
    }]
}');
    
    let filteredUsers=usersObj.users.filter(function(item) { 
   return item.name !== "Juan" && item.name !== "Alex";  
});
    
    console.log(filteredUsers);

More info .