How can I compare a variable with each and every element of an array
var saludo = ["hi", "hola", "buenos dias", "buen dia"];
if(otraVariableX == saludo[]) {
alert("Hola!!!");
}
only the if works for me if I specify the positions of the example array:
saludo[0]
saludo[1]
But I want it to be compared with all the elements of the arrangement, 4 in this case greeting [0-3]
You can use a for to go through the whole arrangement and go comparing.
saludo =["hi", "hola", "buenos dias", "buen dia"];
otraVariableX = "hola";
for (var i = 0; i < saludo.length; i++) {
if (otraVariableX == saludo[i]) {
alert("Hola!!!");
}
} The Arrays have in a method includes () , to know if an element is contained in a Array , it will return a value booleano , TRUE if it is the opposite case FALSE .
var saludo = ["hi", "hola", "buenos dias", "buen dia"];
if(saludo.includes("hola"))
console.log("Si se encuentra");
else
console.log("No Se encuentra ");Here are some ways to verify your doubt:
saludo.some(function(el){ return el === "hola"}); // si alguno cumple esta condición
//output = true
saludo.includes("hola"); //true o false si existe o no
//output = true
saludo.indexOf("hola"); // si es mayor a -1 existe y retorna su posición
//output = 1
var res = false;
saludo.forEach(function(el){
if(el === "hola") res = true;
});
console.log(res); //output = true
One way can be to traverse the arrays with for..in , or with the join () method, in The following example shows you the 2 ways (among others):
var saludo = ["hi", "hola", "buenos dias", "buen dia"];
var otraVariableX = prompt("ingresa un saludo");
// Ejemplo con: for..in
for (n in saludo) {
if (otraVariableX == saludo[n]) {
alert("Hola!!! for..in");
}
}
// Ejemplo con: el método join()
if (saludo.join(" ").indexOf(otraVariableX)+1) {
alert("Hola!!! join()");
}