Cycle problem for JavaScript

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4

I have the following code:

leaderboard.length is defined from the server and in my case it is 12 

var l = leaderboard.length;
var i = 0;

for ( ; i < l; i++) {   
    var o = (i + 1) + ". " + name;
}

This will show me the position of the players from 1 to 11

But my problem is that although% co_of% is 11, I want it to show all the positions, but to position 9 it does not show you the number 9 or just:

1 - Player 1
2 - Player 2
3- Player 3
4- Player 4
5- Player 5
6- Player 6
7- Player 7
8- Player 8
- Player 9
10 - Player 10
11 - Player 11

    
asked by Eduardo Sebastian 19.04.2017 в 16:27
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3 answers

3

Or you could use a IF 

var l = leaderboard.length;
var i = 0;

for ( ; i < l; i++) {

 if(i==8){
 var o = ". " + name;
 }else{
 var o = (i + 1) + ". " + name;
 }
    
answered by 19.04.2017 / 16:35
source
5

You can use the ternary operator A ? B : C 

l = leaderboard.length;
i = 0;

for( ; i < l; i++ ) {

  o = ( i == 8 ) ? ( name ) : ( (i + 1) + ". " + name );
}

Said operator evaluates A and, if true , returns B . Otherwise, it returns C .

    
answered by 19.04.2017 в 16:30
1

Keep in mind that you are evaluating from 0 what means that the results will be in the range of 0 ~ 11 < 12 so the values from 1 to 12 will be displayed, I leave the result in the following example: 

var l = 12;//leaderboard.length;
var i = 0;
var name = "Jugador n";

for ( ; i < l; i++) {   
    var o = (i + 1) + ". " + name;
    console.log(o);
}

The correct thing would be: 

var leaderboard="123456789012";
var name = "Jugador n";

for (i = 1; i < leaderboard.length; i++) {
 var o = (i==9) ? name : i+". "+name;
 console.log(o);
}
    
answered by 19.04.2017 в 17:29
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